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LeetCode - Reverse Integer - Python
Views: 12 | Author: abh
class Solution:
    def reverse(self, x):
        if x < 0: n = -1; x = x * (-1)
        else: n = 1
        r = 0
        while x > 0:
            r = (r * 10) +  x % 10
            x//=10
        r = r * n
        #r = int(str(x)[::-1]) * n
        if r < -2**31 or r > ((2**31) -1): return 0
        return r
        

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