LeetCode - Fibonacci Number - Rust

Views: 174 | Author: abh

```
impl Solution {
pub fn fib(n: i32) -> i32 {
if (n == 0){
return 0;
}
if (n == 1){
return 1;
}
let mut f=0;
let mut s=1;
let mut t;
for _ in 0..n+1{
t = f + s;
s = f;
f = t;
}
return s;
}
}
```

abh
2023-11-02 09:06

I done it with variables insted of array, because I don't know about them at that time.

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