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LeetCode - Minimum Number of Operations to Make Elements in Array Distinct - Python
Views: 9 | Author: abh
class Solution:
    def minimumOperations(self, nums: List[int]) -> int:
        l = len(nums)
        seen = set()
        for n in reversed(nums):
            if n in seen:
                break
            seen.add(n)
            l -= 1
        return (l // 3) + int(bool(l%3))

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